CSIR UGC NET 2024 – Notification, Dates, Application Form, Exam Pattern, Syllabus, Result
CSIR NET 2024 – The CSIR National Eligibility Test (NET) 2024 is more than just a test; it is a doorway into a world of scientific discovery and invention. CSIR NET 2024 is the key to unlocking opportunities in research and education for prospective scientists and educators in India. In this post, we will look at the relevance and impact of the CSIR NET 2024, and why it is such an important step for individuals wishing to establish a name for themselves in the field of science and technology. The 2024 CSIR NET Exam will be conducted in two sessions, i.e.June and December.
What is CSIR NET Exam?
The CSIR NET (Council of Scientific and Industrial Research National Eligibility Test) is an important examination held in India to identify and select individuals who have a strong interest in scientific research and education. This exam, administered by the Council of Scientific and Industrial Research (CSIR), the country’s primary research and development organization, provides a doorway to a career in academics and research. Life Sciences, Physical Sciences, Chemical Sciences, Mathematical Sciences, and Earth Sciences are among the science subjects represented in the CSIR NET. It assesses candidates’ knowledge, ability, and topic competence, allowing them to be considered for Junior Research Fellowship (JRF) or lectureship posts at Indian universities and colleges subject to fulfillment of the eligibility requirements laid down by the UGC..
CSIR NET 2024 Highlights
| Full Form | Council of Scientific and Industrial Research National Eligibility Test |
| Exam Name | CSIR UGC NET |
| Exam Conducting Body | National Testing Agency |
| Frequency of Conduction | Twice a year (June and December) |
| Mode of Application | Online |
| Application Fee (General) | Rs 1150 |
| Mode of Examination | Online |
| Mode of Counseling | Online |
| Duration of the Exam | 3 Hours |
| Official Website | csirnet.nta.nic.in |
CSIR NET 2024 June Important Dates
- Submission of Online Application Form : 01.05.2024 to 21.05.2024
- Last date for successful transaction of Examination fee : 22.05.2024 to 23.05.2024 (upto 11:50 PM)
- Correction in the Particulars of Application Form online only : 25.05.2024 to 27.05.2024
- City Intimation Slip : To be announced later through the website.
- Downloading of Admit Card by the Candidate from NTA Website : To be announced later through the website.
- Date of Examination Schedule : 25, 26 & 27th June, 2024
- Timing of Examination : Will be announced on NTA website
- Centre, Date and Shift of Joint CSIR-UGC NET Examination : As mentioned on the Admit Card
- Display of Recorded Responses and Answer Keys : Will be announced later on website
- Declaration of Result on NTA Website : Will be announced later on website
CSIR NET Notification 2024
The most recent CSIR NET 2024 Notification includes crucial information for prospective applicants, including details on the selection process, syllabus, eligibility requirements, exam structure, and more. This notification serves as a valuable resource for candidates to aid in their exam preparation and to verify whether they meet the eligibility criteria. Candidates will be able to access and download the CSIR NET 2024 notification from the official website for CSIR NET 2024 (https://csirnet.nta.nic.in/).
CSIR NET 2024 Application Form
The CSIR NET application form is the official document that aspiring candidates must complete and submit to apply for the Council of Scientific and Industrial Research (CSIR) National Eligibility Test (NET). This form is a crucial initial step in the application process, and it allows candidates to express their intent to participate in the examination.
How to apply to CSIR NET 2024?
Online Registration: Visit the official CSIR website (www.csirnet.nta.nic.in). Look for the link to “Apply Online” for the CSIR NET 2024 examination.
Fill in Basic Details: Start by registering with your email ID and phone number. You will receive an application number and password for future access.
Complete the Application Form: Log in using the application number and password provided. Fill out the online application form, providing accurate and complete information. You will need to enter personal details, educational qualifications, subject preferences, category details, and other relevant information.
Enter the Security Pin given at the bottom of the CSIR NET 2024 application form registration page and click the ‘Submit’ button.
Select Examination Centers and Specializations: Choose the examination centers where you prefer to take the CSIR NET 2024 exam. You will typically have the option to select multiple centers. You also have to select the specialization in which you want to give the exam to proceed further in the CSIR NET 2024 Application Form. Enter the Security Key once both the exam city and specialization are selected and then click on ‘Submit’.
Upload Documents: Scan and upload your recent passport-sized photograph and signature as per the specified format and size guidelines. If applicable, upload any other required documents, such as category certificates.
Pay the Application Fee: Pay the application fee using the available online payment methods (credit/debit cards, net banking, or UPI). The application fee varies depending on the category you belong to and the number of subjects you select for the exam.
Review and Submit: Carefully review all the information provided in the application form. After ensuring that all details are accurate, submit the application.
Print Application Form: After submission, you can download and print a copy of the completed application form. This is for your reference and may be required for future correspondence.
Confirmation: You should receive a confirmation email or SMS regarding the successful submission of your CSIR NET application.
CSIR NET: Documents Required
The following documents are essential when applying for CSIR NET 2024 Exam:-
- Photo and signature scanned.
- Certificate for Caste, PwD or EWS if applicable
- Credit / Debit card, Internet banking fee payment information
- Correct email identification and contact number.
CSIR NET Application Fee
The following is the CSIR NET 2024 Application Fee for all the categories:-
| Category | Application Fee |
| General/EWS | Rs. 1150 |
| OBC (Non-Creamy Layer) | Rs. 600 |
| SC/ST/PwD/Third Gender | Rs. 325 |
CSIR NET 2024 Eligibility Criteria
The Council of Scientific and Industrial Research (CSIR) lays down certain criterias in order for the candidate to be eligible for the CSIR NET 2024. The following is the CSIR NET 2024 Eligibility Criteria as laid down by the Council of Scientific and Industrial Research :-
Eligibility Criteria- Nationality
- The candidate should be an Indian national so as to give the CSIR NET 2024 Examination.
Eligibility Criteria- Qualification
The following is the Eligibility criteria pertaining to the educational qualifications of the candidates:-
- General/ Unreserved/ General-EWS candidates who have secured at least 55% marks (without rounding off) in Master’s Degree or equivalent examination from recognized universities/ institutions are eligible for this Test. The Other Backward Classes (OBC) belonging to Non-Creamy Layer/Scheduled Caste (SC)/ Scheduled Tribe (ST)/ Persons with Disability (PwD)/ Third gender category candidates who have secured at least 50% marks (without rounding off) in Master’s degree or equivalent examination are eligible for this Test.
- Candidates who are pursuing their Master’s degree or equivalent course or candidates who have appeared for their qualifying Master’s degree (final year) examination and whose result is still awaited or candidates whose qualifying examinations have been delayed may also apply for this test. However, such candidates will be admitted provisionally and shall be considered eligible for NET, only after they have passed their Master’s Degree or equivalent examination with at least 55% marks (50% marks in case of OBC-NCL/ SC/ ST/ PwD/ Third gender category candidates). Such candidates must complete their Master’s degree or equivalent examination within two years from the date of NET result with required percentage of marks, failing which they shall be treated as disqualified.However, those candidates who qualify for ‘Admission to Ph.D. Only’ must complete their Master’s degree or equivalent examination within one year from the date of NET result with required percentage of marks, failing which they shall be treated as disqualified.
- Candidates belonging to the Third gender category are eligible to draw the same relaxation in fee, age and Eligibility Criteria for NET as are available to SC/ST/PwD categories. The subject-wise qualifying cut-offs for this category would be the lowest among those for SC/ ST/ PwD/ OBC–NCL/ General-EWS categories in the corresponding subject.
- The Ph.D. degree holders whose Master’s level examination have been completed by 19 September 1991 (irrespective of date of declaration of result) shall be eligible for a relaxation of 5% in aggregate marks (i.e. from 55% to 50%) for appearing in NET.
- Candidates are neither required to send any certificates/documents in support of their eligibility nor printout of their Application Form or Confirmation Page to NTA. However, the candidates, in their own interest, must ensure themselves about their eligibility for the test. In the event of any ineligibility being detected by the CSIR/UGC/NTA at any stage, their candidature will be cancelled, and they shall be liable for legal action. NTA does not verify the information provided by the candidates during online registration and hence candidature will be purely provisional subject to the fulfillment of eligibility criteria.
- Candidates with post-graduate diploma/ certificate awarded by Indian University/ Institute or foreign degree/ diploma/ certificate awarded by the foreign University/ institute should in their own interest, ascertain the equivalence of their diploma/degree/ certificate with Master’s degree of recognized Indian universities from Association of Indian Universities (AIU), New Delhi (www.aiu.ac.in).
- The candidates having passed a 4-year/8-semester bachelor’s degree programme should have a minimum of 75% marks in aggregate or its equivalent grade on a point scale wherever the grading system is followed. A relaxation of 5% marks or its equivalent grade may be allowed for those belonging to SC/ ST/ OBC (non-creamy layer)/ Differently-Abled, Economically Weaker Section (EWS) and other categories of candidates as per the decision of the Commission from time to time (refer to University Grants Commission (Minimum Standards and Procedures for Award of Ph.D. Degree) Regulations, 2022 https://www.ugc.gov.in/pdfnews/0909572_Minimum-Standards-and-Procedure-for-Awardof-PhD-Degree.pdf). The candidates qualifying in the NET, based on a four-year undergraduate degree, will be eligible for the award of the Junior Research Fellowship (JRF) and for admission to the Ph.D. The candidates qualifying in the NET, based on a four-year undergraduate degree, will not be eligible for appointment as Assistant Professor.
- The candidates who are pursuing Four Year/8 Semester Bachelor’s Degree Programme and are in their last semester/year may also apply for the test. However, such candidates will be admitted provisionally and shall be considered eligible for the award of JRF/admission to Ph.D. only after fulfilling the requirements contained in the University Grants Commission (Minimum Standards and Procedures for Award of Ph.D. Degree) Regulations, 2022 within two years (if qualified for award of JRF)/within one year (if qualified for admission to Ph.D. only) from the date of declaration of the NET result, failing which they shall be treated as disqualified.
- The candidates with a Four-Year Bachelor’s Degree Programme are allowed to appear in a subject (the List of Subjects and their Codes for Joint CSIR-UGC NET June 2024 are given at (Annexure-II) in which they want to pursue a Ph.D. irrespective of the discipline in which they have obtained the four-year bachelor’s degree.
Upper Age limit:
- JRF: Not more than 30 years as on the 1st day of the month in which the examination is concluded i.e. June, 2024. A relaxation of upto 5 years is provided to the candidates belonging to OBC-NCL (as per the Central list of OBC available on website: www.ncbc.nic.in) /SC/ST/PwD/Third gender categories and to women applicants.
- Assistant Professor: There is no upper age limit in applying for Joint CSIR UGC-NET for Assistant Professor.
- Admission to PhD: There is no upper age limit in applying for Joint CSIR-UGC-NET for Admission to PhD.
CSIR NET Exam Pattern
The CSIR NET 2024 exam pattern consists of five papers. The exam is conducted to assess the eligibility of candidates for Junior Research Fellowship (JRF) and lectureship in various science disciplines. Below is the general exam pattern:
| Subjects | Number of questions asked |
| Life Sciences | 145 |
| Physical Sciences | 75 |
| Chemical Sciences | 120 |
| Mathematical Sciences | 120 |
| Earth Sciences | 150 |
The CSIR NET 2024 exam is held in a computer-based test (CBT) mode.Candidates must select one of the five subjects (Life Sciences, Physical Sciences, Chemical Sciences, Mathematical Sciences, Earth Sciences) during the application process, based on their academic background and expertise. The exam is of a total of 200 marks and is of 3 hours. Each question carries 2 marks. Negative marking applies, however is different for each part of the subject tested upon. (25% for some parts while it is 33% for others)
The question paper will be divided into three sections:
Section A: This section will be common to all subjects and will consist of a maximum of 20 General Aptitude questions. Candidates must answer any 15 of these questions, each carrying two marks. The total marks for this section will be 30 out of 200.
Section B: This part will contain subject-specific multiple-choice questions (MCQs). It will contribute 70 marks out of the total 200 marks. The number of questions to be attempted in this section will vary between 20 and 35.
Section C: In this section, candidates will encounter higher value questions that may assess their understanding of scientific concepts and their ability to apply these concepts analytically to solve scientific problems. This section will be worth 100 marks out of 200.
CSIR NET 2024 Exam Pattern for Life Sciences
The candidate must answer a maximum of 15, 35, and 25 questions from Parts A, B, and C, respectively. If more than the requisite number of questions are answered, only the first 15, 35, and 25 questions in Part A, Part B, and Part C will be evaluated. Four possibilities or responses are provided for each question in Parts A, B, and C.
The following is the Exam Pattern for Life Sciences:-
| CSIR NET Life Science Exam Pattern | ||||
| Sections | Total Questions | Questions to attempt | Marks Allotted | Negative marking |
| Part A | 20 | 15 | 2 | 0.5 |
| Part B | 50 | 35 | 2 | 0.5 |
| Part C | 75 | 25 | 4 | 1 |
| Total | 145 | 75 | 200 | – |
CSIR NET 2024 Exam Pattern for Physical Sciences
The candidate must answer a maximum of 15, 20, and 20 questions from Parts A, B, and C, respectively. If more than the requisite number of questions are answered, just the top 15, 20, and 20 questions in Part A, Part Band, and Part C will be evaluated. Four possibilities or responses are provided for each question in Parts A, B, and C. Only one of these options is the “correct” answer to the question.
The following is the Exam Pattern for Physical Sciences:-
| CSIR NET Paper Pattern for Physical Science | ||||
| Section | Total Questions | Max No of Questions to attempt | Marks for each correct answer | Negative marking |
| Part A | 20 | 15 | 2 | 0.5 |
| Part B | 25 | 20 | 3.5 | 0.875 |
| Part C | 30 | 20 | 5 | 1.25 |
| Total | 75 | 55 | 200 | – |
CSIR NET 2024 Exam Pattern for Chemical Sciences
The candidate must answer a maximum of 15, 35, and 25 questions from Parts A, B, and C, respectively. If more than the requisite number of questions are answered, only the first 15, 35, and 25 questions in Part A, Part B, and Part C will be evaluated. Four possibilities or responses are provided for each question in Parts A, B, and C. Only one of these options is the “correct” answer to the question. The candidate must find the correct or best solution to each question.
The following is the Exam Pattern for Chemical Sciences:-
| CSIR NET Exam Pattern for Chemical Science | ||||
| Section | Total Questions | Questions to Attempt | Marks Allocated | Negative marking |
| Part A | 20 | 15 | 2 | 0.5 |
| Part B | 40 | 35 | 2 | 0.5 |
| Part C | 60 | 25 | 4 | 1 |
CSIR NET 2024 Exam Pattern for Mathematical Sciences
The candidate must answer a maximum of 15, 25, and 20 questions from Parts A, B, and C, respectively. If more than the required number of questions are answered, only the first 15, 25, and 20 questions in Parts A, B, and C will be evaluated. Four possibilities or responses are provided for each question in Part A and Part B. Only one of these options is the “correct” answer to the question. For each question, the candidate must find the correct or best solution. Part C questions may have “ONE” or “MORE” correct answers. Credit for a question will be provided only if “ALL” of the right alternatives in Part C are identified.
The following is the Exam Pattern for Mathematical Sciences:-
| CSIR NET Exam Pattern for Mathematical Science | ||||
| Sections | Total Questions | Questions to attempt | Marks Allotted | Negative marking |
| Part A | 20 | 15 | 2 | 0.5 |
| Part B | 40 | 25 | 3 | 0.75 |
| Part C | 60 | 20 | 4.75 | 0 |
| Total | 120 | 60 | 200 | – |
CSIR NET 2024 Exam Pattern for Earth Sciences
The candidate must answer a maximum of 15, 35, and 25 questions from Parts A, B, and C, respectively. If more than the requisite number of questions are answered, only the first 15, 35, and 25 questions in Part A, Part B, and Part C will be evaluated. Four possibilities or responses are provided for each question in Parts A, B, and C. Only one of these options is the “correct” answer to the question. For each question, the candidate must find the correct or best solution.
The following is the Exam Pattern for Earth Sciences:-
| CSIR NET Exam Pattern for Earth Sciences | ||||
| Sections | Total Questions | Questions to Attempt | Marks Allotted | Negative marking |
| Part A | 20 | 15 | 2 | 0.5 |
| Part B | 50 | 35 | 2 | 0.5 |
| Part C | 80 | 25 | 4 | 1.32 |
| Total | 150 | 75 | 200 | – |
CSIR NET Syllabus 2024
The syllabus for the CSIR NET 2024 differs based on the subject chosen for the examinations. Life Sciences, Physical Sciences, Chemical Sciences, Mathematical Sciences, and Earth Sciences are among the science disciplines tested. The basic syllabus for CSIR NET 2024 is provided below:-
| Subjects | Syllabus |
| Life Sciences |
|
| Physical Sciences |
|
| Chemical Sciences |
|
| Mathematical Sciences |
|
| Earth Sciences |
|
For more information, candidates should refer to the subject-specific syllabus provided in the official CSIR NET 2024 notice when released. To thrive in the examination and qualify for Junior Research Fellowship (JRF) or lectureship positions in their respective fields of study, students must prepare according to the subject-specific syllabus.
CSIR NET Previous Year Question Papers
CSIR NET previous year question papers are invaluable study materials for candidates preparing for this competitive examination. These papers offer firsthand insights into the exam’s format, question types, and difficulty levels. By solving these papers, candidates can gauge their readiness, identify areas that need improvement, and refine their time-management skills. Moreover, since the CSIR NET 2024 syllabus is extensive, practicing with past papers helps candidates prioritize their study efforts based on the recurring topics.
The CSIR NET Previous Year Question Papers can be found online. For the ease of the candidates we are providing the PDF links to the CSIR NET 2022 Question Papers:-
| Question Paper | PDF Link |
| Life Sciences Shift-1 | Life Sciences 1.pdf |
| Life Sciences Shift-2 | Life Sciences 2.pdf |
| Physical Sciences | Physical Sciences.pdf |
| Chemical Sciences | Chemical Sciences.pdf |
| Mathematical Sciences | Mathematical Sciences.pdf |
| Earth Sciences | CSIR Earth Atmospheric Ocean N Planetary Science.pdf |
In addition to this, the official HRDG website (https://csirhrdg.res.in/Home/Index/1/Default/2725/79) also provides the candidates with model question papers for all the subjects, the links for which are given below:-
| Subjects | Model Question Paper |
| Life Sciences | |
| Physical Sciences | |
| Chemical Sciences | |
| Mathematical Sciences | |
| Earth Sciences |
CSIR NET 2024 Admit Card
The CSIR NET 2024 admit card is a crucial document that candidates must download and carry to the examination center on the day of the exam.
Here is how you can download the CSIR NET 2024 admit card:-
- Visit the Official CSIR NET 2024 Website: Go to the official CSIR NET 2024 website. The URL for the website may vary, so you should check the latest notification or search for it online.
- Login to Your Account: Look for the “Admit Card” or “Download Admit Card” link on the website’s homepage.Click on the link to access the admit card download page.
- Enter Login Credentials: You will be prompted to enter your login credentials, which typically include your application number and password or date of birth. Make sure to enter these details accurately.
- Admit Card Download: Once you’ve entered the required information, click the “Submit” or “Download Admit Card” button. Your CSIR NET 2024 admit card should be displayed on the screen.
- Verify Details: Carefully review all the details on the admit card, such as your name, photograph, signature, exam date, time, and venue. Ensure that all the information is correct. If you find any discrepancies, contact the CSIR NET authorities immediately for resolution.
- Download and Print: After verifying the details, click on the “Download” or “Print” button to save a copy of your admit card to your device. Take a printout of the admit card. It is advisable to print multiple copies for backup.
CSIR NET Admit Card- Details Mentioned
The following details should be mentioned in the candidate’s admit card for it to be valid when giving the CSIR NET 2024 Exam:-
- Personal Details
- Roll Number
- Name of the Candidate
- Date of Birth
- Category
- Father’s Name
- Gender
- Application Number
- Photograph and Signature
- Person With Disability (Yes/No)
- Examination Details
- Reporting Time
- Subject(s) Applied For
- Center Number
- Address of the Centre
- Time of Gate Closing
- Time of the Exam
- Shift (First Or Second)
- Important Instructions
- COVID-19 Undertaking Form
CSIR NET Exam Centre
The following are the CSIR NET 2024 Exam Centres:-
| State/UT Name | City | Code |
| Andaman & Nicobar Islands | Port Blair | AN01 |
| Andhra Pradesh | Anantapur | AP01 |
| Bhimavaram | AP03 | |
| Chirala | AP04 | |
| Chittoor | AP05 | |
| Eluru | AP06 | |
| Guntur | AP07 | |
| Kadapa | AP08 | |
| Kakinada | AP09 | |
| Kurnool | AP10 | |
| Nellore | AP11 | |
| Ongole | AP12 | |
| Rajahmundry | AP13 | |
| Srikakulam | AP14 | |
| Tirupati | AP16 | |
| Vijayawada | AP17 | |
| Visakhapatnam | AP18 | |
| Vizianagaram | AP19 | |
| Narasaraopet | AP20 | |
| Proddatur | AP21 | |
| Surampalem | AP23 | |
| Arunachal Pradesh | Itanagar/ Naharlagun | AL01 |
| Assam | Dibrugarh | AM01 |
| Guwahati | AM02 | |
| Jorhat | AM03 | |
| Silchar | AM04 | |
| Tezpur | AM05 | |
| Bihar | Bhagalpur | BR02 |
| Darbhanga | BR04 | |
| Gaya | BR05 | |
| Muzaffarpur | BR06 | |
| Patna | BR07 | |
| Purnea | BR08 | |
| Arrah | BR09 | |
| Chandigarh (ut) | Chandigarh/Mohali | CH01 |
| Chhattisgarh | Bhilai/Durg/Bhilai Nagar | CG01 |
| Bilaspur (CG) | CG02 | |
| Raipur | CG03 | |
| Dadra & Nagar Haveli & Daman & Diu (UT) | Dadra & Nagar Haveli | DN01 |
| Daman | DD01 | |
| Diu | DD02 | |
| Delhi | Delhi/New Delhi | DL01 |
| Goa | Panaji/Madgaon | GO01 |
| Gujarat | Ahmedabad/Gandhinagar | GJ01 |
| Anand | GJ02 | |
| Bhavnagar | GJ03 | |
| Jamnagar | GJ06 | |
| Junagadh | GJ07 | |
| Mehsana | GJ08 | |
| Rajkot | GJ10 | |
| Surat | GJ11 | |
| Vadodara | GJ12 | |
| Valsad/Vapi | GJ13 | |
| Himatnagar | GJ14 | |
| Haryana | Ambala | HR01 |
| Faridabad | HR03 | |
| Gurugram | HR04 | |
| Hissar | HR05 | |
| Karnal | HR06 | |
| Kurukshetra | HR07 | |
| Panipat | HR08 | |
| Sonipat | HR09 | |
| Yamuna Nagar | HR10 | |
| Himachal Pradesh | Bilaspur (HP) | HP01 |
| Hamirpur | HP03 | |
| Kangra/ Palampur | HP04 | |
| Shimla | HP06 | |
| Solan | HP07 | |
| Mandi | HP08 | |
| Una | HP09 | |
| Kullu | HP10 | |
| Jammu & Kashmir | Baramulla | JK01 |
| Jammu | JK02 | |
| Samba | JK03 | |
| Srinagar | JK04 | |
| Jharkhand | Bokaro Steel City | JH01 |
| Dhanbad | JH02 | |
| Jamshedpur | JH03 | |
| Ranchi | JH04 | |
| Hazaribagh | JH05 | |
| Karnataka | Belagavi (Belgaum) | KK02 |
| Bellary | KK03 | |
| Bengaluru | KK04 | |
| Bidar | KK05 | |
| Davangere | KK06 | |
| Gulbarga | KK08 | |
| Hassan | KK09 | |
| Hubli | KK10 | |
| Mangaluru | KK12 | |
| Mysuru | KK14 | |
| Shivamogga | KK15 | |
| Tumakuru | KK16 | |
| Manipal/Udupi | KK17 | |
| Mandya | KK18 | |
| Kerala | Alappuzha/Chengannur | KL01 |
| Ernakulam/Angamaly/Muvattupuzha | KL04 | |
| Idukki | KL05 | |
| Kannur | KL07 | |
| Kasaragod | KL08 | |
| Kollam | KL09 | |
| Kottayam | KL11 | |
| Kozhikode | KL12 | |
| Malappuram | KL13 | |
| Palakkad | KL15 | |
| Pathanamthitta | KL16 | |
| Thiruvananthapuram | KL17 | |
| Thrissur | KL18 | |
| Ladakh | Leh | LL01 |
| Lakshadweep (UT) | Kavaratti | LD01 |
| Madhya Pradesh | Balaghat | MP01 |
| Betul | MP02 | |
| Bhopal | MP03 | |
| Chhindwara | MP05 | |
| Gwalior | MP06 | |
| Indore | MP07 | |
| Jabalpur | MP08 | |
| Rewa | MP11 | |
| Sagar | MP12 | |
| Satna | MP13 | |
| Ujjain | MP15 | |
| Maharashtra | Ahmednagar | MR01 |
| Akola | MR02 | |
| Amravati | MR03 | |
| Aurangabad (MR) | MR04 | |
| Chandrapur | MR09 | |
| Dhule | MR10 | |
| Jalgaon | MR13 | |
| Kolhapur | MR14 | |
| Latur | MR15 | |
| Mumbai | MR16 | |
| Nagpur | MR17 | |
| Nanded | MR18 | |
| Nasik | MR19 | |
| Pune | MR22 | |
| Raigad | MR23 | |
| Ratnagiri | MR24 | |
| Sangli | MR25 | |
| Satara | MR26 | |
| Solapur | MR27 | |
| Thane | MR28 | |
| Wardha | MR29 | |
| Manipur | Imphal | MN01 |
| Churachandpur | MN02 | |
| Meghalaya | Shillong | MG01 |
| Mizoram | Aizawl | MZ01 |
| Nagaland | Dimapur | NL01 |
| Kohima | NL02 | |
| Odisha | Balasore | OR02 |
| Behrampur(Ganjam) | OR03 | |
| Bhubaneshwar | OR04 | |
| Cuttack | OR05 | |
| Dhenkanal | OR06 | |
| Rourkela | OR08 | |
| Sambalpur | OR09 | |
| Puducherry | Puducherry/ Cuddalore | PO01 |
| Punjab | Amritsar | PB01 |
| Bhatinda | PB02 | |
| Jalandhar | PB04 | |
| Ludhiana | PB05 | |
| Pathankot | PB07 | |
| Patiala | PB08 | |
| Sangrur | PB11 | |
| Rajasthan | Ajmer | RJ01 |
| Alwar | RJ02 | |
| Bikaner | RJ05 | |
| Jaipur | RJ06 | |
| Jodhpur | RJ07 | |
| Kota | RJ08 | |
| Sikar | RJ09 | |
| Sriganganagar | RJ10 | |
| Udaipur | RJ11 | |
| Sikkim | Gangtok | SM01 |
| Tamil Nadu | Chennai | TN01 |
| Coimbatore | TN02 | |
| Cuddalore | TN03 | |
| Kanchipuram | TN05 | |
| Kanyakumari/ Nagercoil | TN06 | |
| Madurai | TN08 | |
| Namakkal | TN10 | |
| Salem | TN11 | |
| Thanjavur | TN12 | |
| Thoothukudi | TN13 | |
| Tiruchirappalli | TN14 | |
| Tirunelveli | TN15 | |
| Tiruvallur | TN16 | |
| Vellore | TN18 | |
| Virudhunagar | TN20 | |
| Telangana | Hyderabad | TL01 |
| Karimnagar | TL02 | |
| Khammam | TL03 | |
| Mahbubnagar | TL04 | |
| Nalgonda | TL05 | |
| Warangal | TL07 | |
| Tripura | Agartala | TA01 |
| Uttar Pradesh | Agra | UP01 |
| Aligarh | UP02 | |
| Allahabad | UP03 | |
| Bareilly | UP04 | |
| Faizabad | UP06 | |
| Ghaziabad | UP07 | |
| Gorakhpur | UP08 | |
| Greater Noida/Noida | UP09 | |
| Jhansi | UP10 | |
| Kanpur | UP11 | |
| Lucknow | UP12 | |
| Mathura | UP13 | |
| Meerut | UP14 | |
| Moradabad | UP15 | |
| Muzaffarnagar | UP16 | |
| Sitapur | UP17 | |
| Varanasi | UP18 | |
| Uttarakhand | Dehradun | UK01 |
| Haldwani | UK02 | |
| Haridwar | UK03 | |
| Nainital | UK04 | |
| Pantnagar | UK05 | |
| Roorkee | UK06 | |
| West Bengal | Asansol | WB01 |
| Bardhaman | WB02 | |
| Durgapur | WB04 | |
| Hooghly | WB06 | |
| Howrah | WB07 | |
| Kalyani | WB08 | |
| Kolkata | WB10 | |
| Siliguri | WB11 |
CSIR NET Result 2024
The CSIR NET 2024 Result has not yet been released. Once released the candidate will then be able to access it from the official website itself.
How to check CSIR NET 2024 Result?
Candidates who have taken the CSIR NET 2024 exam can access their results by following these steps:
- Go to the official CSIR NET 2024 website.
- Find and click on the link for CSIR NET 2024 results on the homepage.
- The CSIR NET2024 result login page will appear.
- Provide your CSIR NET 2024 application number and date of birth as per your application.
- Enter the security pin as displayed.
- Submit the required details.
- Your CSIR NET 2024 results for both the December and June sessions will then be displayed on the screen.
CSIR NET Result: Details Mentioned
The following details should be mentioned in the CSIT NET 2024 Result:-
- Roll Number
- Rank
- Total Number of Qualified Candidates
CSIR NET Cutoff
The CSIR NET 2024 cutoff marks are determined based on various factors, including the number of candidates appearing for the exam, the difficulty level of the question paper, and the category of the candidate. For more clarity we have provided the CSIR NET 2023 expected cut-off since the CSIR NET 2024 cut off has not yet been released:-
| JRF | ||||||
| Name of Subject | Unreserved | EWS | OBC | SC | ST | PWD |
| Chemical Science | 47–55 | 49–52 | 41–47 | 33–39 | 26–29 | 25–26 |
| Earth Science | 56–64 | 55–60 | 48–57 | 42–48 | 41–44 | 29–33 |
| Life Science | 45–54 | 46–50 | 45–47 | 38–40 | 33–34 | 25–27 |
| Mathematical Science | 47–53 | 48–52 | 46–50 | 35–37 | 27–28 | 25–26 |
| Physical Science | 51–54 | 44–48 | 44–48 | 30–27 | 27–30 | 25–28 |
| Lectureship | ||||||
| Chemical Science | 43–49 | 45–47 | 37–42 | 25–26 | 30–35 | 25–26 |
| Earth Science | 51–57 | 50–54 | 47–51 | 37–39 | 40–44 | 26–27 |
| Life Science | 49–51 | 42–45 | 40–43 | 29–30 | 34–37 | 23–25 |
| Mathematics Science | 48–51 | 43–46 | 41–44 | 25–26 | 31–33 | 23–25 |
| Physical Science | 45–50 | 40–43 | 39–43 | 25–28 | 29–33 | 25–26 |
CSIR NET Answer Key
CSIR NET 2024 Answer Key has not yet been released. The CSIR NET Answer Key is released by CSIR after the exam and is made available for each subject. Candidates have the opportunity to challenge the provisional answer key within a specified period. After addressing objections, CSIR releases the final answer key, which serves as an official reference for candidates to evaluate their performance in the exam.
CSIR NET Salary
The following are the salary details of candidates who get selected via the CSIR NET:-
| Post | Salary |
| Junior Research Fellows | Rs. 31,000 +HRA (Depends on the Institution) |
| Senior Research Fellows | Rs. 35,000+HRA (Depends on the Institution) |
| Assistant Professor | Rs.45,000 |
| Associate Professor | Rs. 80,000 |
| Professor | Rs. 82,000 |
CSIR NET Books
Students can check out the below mentioned list of books for CSIR NET Preparation:-
| Book Name | Publisher/Author | Section Covered |
| Lehninger Principles of Biochemistry | Nelson and Cox | Life Science |
| Molecular Cell Biology | Lodish | Life Science |
| Physical Chemistry | Thomas Engel & Philip Reid | Chemical Sciences |
| Concise Inorganic Chemistry | J. D. Lee | Chemical Sciences |
| Classical Mechanics | J C Upadhya | Physical Sciences |
| Solid State Physics | Neil W Ashcroft | Physical Sciences |
| CSIR-UGC NET/JRF/SET Mathematical Sciences | Alok Kumar (Upkar) | Mathematical Sciences |
| Real Analysis | H. L. Royden | Mathematical Sciences |
| Classical Mechanics | Herbert Goldstein | Mathematical Sciences |
| An Objective Earth Sciences | S Ahmad | Earth Sciences |
| Climatology and Oceanography | D.S Lal | Earth Sciences |
| Earth, Atmospheric, Ocean, and Planetary Sciences Exam Guide (Part B & C) | Surender. K | Earth Sciences |
CSIR NET Preparation Tips
- Understand the Exam Pattern: CSIR NET has three parts: Part A (General Aptitude), Part B (Subject-related), and Part C (Subject-related). Make sure you understand the weightage and format of each section.
- Choose Your Subject Wisely:Select a subject that aligns with your academic background and interests. You’ll perform better if you have a strong foundation in your chosen subject.
- Gather Study Material:Get the recommended textbooks and study materials for your subject. Consult your professors or mentors for suggestions if needed.
- Create a Study Plan:Develop a detailed study plan that covers all the topics in the syllabus. Allocate time for each topic, and be consistent with your study routine.
- Focus on Basics:Start with the basics and gradually move to more advanced topics. Ensure you have a solid understanding of the fundamental concepts.
- Solve Previous Year Question Papers:Practicing previous year question papers can help you understand the exam pattern and the type of questions asked. It’s an excellent way to gauge your preparation.
- Join Coaching or Online Courses:Consider enrolling in coaching classes or online courses if you need additional guidance and structured study materials.
- Take Mock Tests: Regular mock tests will help to assess your progress and improve your time management skills. Analyze your performance to identify weak areas.
- Stay Updated: Keep up with the latest developments in your subject by reading research papers, journals, and news related to your field.
- Revision:Revision is crucial. Allocate sufficient time for revision before the exam. Create concise notes to facilitate quick revision.
CSIR NET 2024 FAQs
Q How many subjects is the CSIR NET 2024 exam conducted for?
Ans The CSIR UGC NET 2024 exam is conducted for a total of five subjects out of which the candidate chooses their specialization and the subject(s) they want to give the exam for.
Q How can I download the CSIR UGC NET admit card 2024?
Ans The CSIR UGC NET 2024 admit card can be downloaded after login in with application number and date of birth.
Q How can I change my CSIR NET 2024 exam center?
Ans You can’t change the CSIR NET Exam Center 2024 after the final application form has been submitted or after the Exam Center has been allocated.
Q Can I give CSIR UGC NET 2024 in offline mode?
Ans No, CSIR UGC NET is conducted in online mode only.
Q For how many years is the CSIR NET score valid?
Ans The CSIR NET score is valid for two years.
Q How many sessions of CSIR NET are there in a year?
Ans The CSIR NET 2024 will be conducted in two sessions, i.e., June and December.
Conclusion
Therefore, studying for the CSIR NET 2024 exam necessitates rigorous planning, effort, and a solid foundation in your chosen field. It is critical to build an organized study plan, practice with previous year exams and mock tests, and stay current on advancements in your profession. Maintaining good physical and mental health, coping with stress, and remaining positive are all critical components of your preparatory journey. You can improve your chances of success in this challenging exam by putting in constant work and using a well-rounded strategy.
Also See :
- CSIR NET Application form
- CSIR NET 2024 Eligibility criteria
- CSIR NET 2024 Exam pattern
- CSIR NET Result
- CSIR NET Admit card 2024