Is Matter around us Pure, Class 9 Science Chapter 2 Notes, Question Answer

Is matter us Pure Class 9 Notes | Video Explanation, Question and Answers

 

Class 9 Science

Chapter 2 – Is Matter around us Pure?

 

is matter around us pure

 

 

 

Video Explanation of Chapter 2 Is matter around us pure

 


 
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Is Matter around us Pure Introduction

We come across different substances like water that we drink; salt that we add in food for taste, milk that we drink as it provides us with calcium and other minerals, soaps that we use to wash clothes, paint that we use to colour walls and so on. These substances have different nature, different properties. They can be pure or there can be some impurities in them. Let us see what do we understand by the words pure or impure substances.
 
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Pure substance

They are substances that are made up of a single type of particle. But there are certain characteristics that determine the purity of a substance. Let us see what all properties they possess.

Characteristics of a pure substance are as follows-

  1. They all have a uniform composition ( homogeneous).
  2. They can not be separated into their constituents.
  3. They have fixed melting and boiling points.
  4. They always have the same characteristic properties.

 

Two categories of substances fall under pure substance. They are as follows-

  1. Elements
  2. Compounds

 
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Element

As we know, an atom is the smallest particle that may or may not exist independently. These atoms unite together and form an element. This element can exist independently but it can not be broken into atoms as they are not visible. About 118 elements are known so far and still many discoveries are in the pipeline. Elements can be prepared artificially in lab, also by transmutation process. The elements having atomic number more than 92 are manmade and are called transuranic elements.

An element is defined as a substance that can not be broken into simpler substances as it is formed of atoms and atoms can not be seen.

The characteristics of elements are as follows-

  1. They are made up of atoms
  2. The physical & chemical properties of an element are due to the arrangement of atoms.
  3. They can occur in nature in free or combined form.
  4. They can be prepared artificially by nuclear reaction.
  5. They can be solids, liquids (only 3) or gases (11) at normal room temperature.

Element

 

elements

 
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metals

 

Metals

In daily routine, we use a lot of substances that fall in this category like the vehicles which are usually made up of iron, furniture, utensils and many more. Let us see their properties.

Those substances which have a tendency to lose electrons and form positively charged species, that is cation are called metals.

Na – 1e- → Na+ (cation)
2, 8, 1 2, 8

Physical properties of metals are as follows-

  • They are malleable like Al(aluminum), Ag(silver) [ except alkali metals that is Na,K,Li etc]
  • They are ductile like Al, Ag, etc.
  • They are lustrous (except – Hg(mercury), Cs(cesium), Ga (gallium)) .
  • They are hard (except Na & K ).
  • They are good conductors of heat & electricity.
  • They have high melting and boiling points [except Na, k, Ca they have low boiling and melting point] .
  • They are Sonorous (that is when hit, they produce a sound).

 

Chemical Properties of metals are as follows-
1. Reaction with oxygen

Metals react with oxygen to form oxides.

M + O2 → Metal oxides

All Metal oxides are basic in nature i.e. they turn red litmus blue but some metal oxides are amphoteric in nature (that is, they have acidic & basic nature) like Al2O3 (aluminum oxide) & ZnO (zinc oxide).

2. Reaction with dilute acids

Metals react with dilute acids to form a salt and H2 gas.

M + HX → MX + H2

Example: Na + HCl → NaCl + H2

The hydrogen gas, when comes in contact with air, burns with a popping sound.
 
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Non-Metals

Non – Metals are those elements that always gain electrons and form anions (negatively – charged ions).

Example: Cl + e- → Cl- anion
2, 8, 7 2, 8, 8

Physical properties of non – metals are as follows-

  • They are liquid or gases (only one exists in liquid form – that is Bromine) except C, S, P, I that are solids.
  • They are non – malleable and non – ductile because to make wires or sheets, we need to hammer them, but as they are brittle, they break.
  • They are bad conductors of heat and electricity (like graphite).
  • They have low melting and boiling point (except B, C which have high melting and boiling points).
  • They are non sonorous.
  • They are non lustrous (except graphite and iodine).

 

Chemical properties of non – metals are as follows-
1. Reaction with oxygen

Non – metals react with O2 to form Non Metal oxide with respective formula as given below:

N + O2 → non metal oxide

They are acidic in nature and turn blue litmus red.

2. Reaction with dilute acids

Non metals do not react with die acids as they do not have sufficient electrons.

 
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Class 9 Science Chapter wise Explanation

 

Metalloids

They are those which have properties similar to metals and non-metals.

Few elements exist as Noble gases. They are those which are stable elements as they have a stable configuration and generally exist free in nature as they do not need to combine with other elements because they have a stable electronic configuration.

The noble gases are He (helium), Ne (neon), Ar (Argon), Kr (krypton), Xe (xenon) and radon.

 
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Compounds

We use so many compounds like salt, water, fertilizers, etc. Let us learn about their properties.

salt

They are formed when 2 or more elements combine in a fixed whole number ratio.

Characteristics of compounds are as follows-

  • They are homogenous.
  • The properties of a compound are entirely different from its constituents.
  • The constituents can not be separated by physical methods.
  • They have fixed properties like Melting point and Boiling point.
  • The formation of compound is accompanied by energy changes.

Example: H2O (water), NaCl (sodium chloride), etc.
 
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Impure substance
The substances that are formed by different kinds of particles are called impure substances.
For example : Mixtures are impure substances.

 
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Mixtures

You must have eaten pakoras at home. Have you noticed how your mother prepares it. She makes a batter containing besan, water, spices, etc. These constituents can be added in any ratio. In all ratios, they will form pakoras but the difference will be that sometimes, they will be hard to touch or the batter may be too loose to fry.

metals

Mixtures: They are formed when two or more substances are simply mixed in any ratio and are not chemically combined with each other.

Characteristics of a mixture are as follows-

  • They can be homogeneous or heterogeneous in nature, that is, the constituents can be seen to have visible boundaries or they may appear to mix thoroughly.
  • The properties of a mixture are the same as that of its constituents.
  • The constituents can be separated by physical methods.
  • Their formation does not require or release energy as there is no bond formation or breakage involved.
  • The properties of mixtures like melting point & boiling point are not fixed.

 
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Types of Mixtures

 

types of mixtures

 

Homogenous
Heterogeneous
It is a mixture that is uniform in its properties & composition.
Example: Air (which is a mixture of gases)
Mixtures that do not have uniform properties & composition throughout.
Example: oil & water

 
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Solutions
We all like drinking sweet lemon water in summers as it gives a cooling effect. It is made of lemon, water, ice, salt and sugar. These all components when mixed, form sweet lemon water mixture which is also called a solution. These components can be separated by using different techniques. Let us learn what exactly solutions are and their types.

solutions

A Solution is a homogenous mixture of two or more substances. To form it, we can add 2 or more components. These components can be in any ratio but are simply mixed, that is not chemically combined. Generally, two components of solutions are seen and are called ‘Solute’ and ‘Solvent’.

Solute
It is the constituent which is present in a comparitively lesser amount and gets dissolved in the solvent.

Solvent
It is the constituent present in more amount and it has the ability to dissolve the solute in it.
If you dissolve salt in water, then the salt is in lesser quantity and it gets dissolved. So, here solute is salt and solvent is water.

Characteristics of solutions are as follows-

  • They are homogeneous.
  • Their Composition can vary.
  • The size of particles is very small.
  • They do not scatter light.
  • They can be separated by physical methods.

Types of solutions

  1. On the basis of dissolving nature of liquids

You must have noticed that when you dissolve sugar or salt in water, it just vanishes after a few seconds or a minute. The reason is that it gets mixed in water. But if we add oil in water, it does not vanish and is seen floating on its surface. It is due to this reason that some substances can mix into each other and some do not. Let us learn about it in detail-

 

 

Miscible, immiscible & partially miscible solutions

 

types of solutions

 

Miscible liquids

The liquids that completely mix into each other to form a solution are miscible liquids.
For example: alcohol when added to water gets completely mixed.

Partially miscible liquids
The liquids which can dissolve in another liquid only up to some extent to form a solution are partially miscible liquids.
For example: ethylene glycol in chloroform.

Immiscible liquids
The liquids which do not mix into each other are immiscible liquids.
For example: oil & water.

  1. On the basis of nature of solvent

We have seen that it’s not only water in which we can dissolve substances, we can make use of other substances as well. For example- carbon tetrachloride, Benzene, alcohol, etc. and many more reagents. So, we have another classification based on the nature of solvent.

Aqueous and Non aqueous solutions

Aqueous
The solution in which the solvent is water is an aqueous solution.
Example: salt solution

Non-aqueous solutions
The solution in which the solvent is other than water is a non-aqueous solution.
Example: alcohol, benzene etc.

  1. Classification on the basis of solubility power of solvent

You must have seen that if you take one glass of water at room temperature and you add 1 spoon of sugar to it, it dissolves. But if you keep on adding sugar to the same solution, a point will be reached when it stops dissolving sugar in it and the sugar starts getting deposited at the bottom. The reason being that each solvent has some solubility power and it can dissolve only up to that limit. Let us study about it.

Saturated, unsaturated and supersaturated solutions

Saturated Solution
The solution that dissolves as much solute as it is capable of dissolving is a saturated solution.

Unsaturated solution
The solution in which more quantity of solute can be dissolved without increasing its temperature is an unsaturated solution.

Supersaturated
The solution in which the solvent dissolves an amount of solute greater than its solubility.
It is formed at high temperature and then slowly cooling it to lower its solubility.

Solubility
Is the amount of solute that can be dissolved in a given amount of solvent at a particular temperature.

Factors affecting solubility

  • Nature of solute.
  • Nature of solvent.
  • Temperature.

Please Note:

    • On lowering temperature, solubility of liquids & solid decreases & solubility of gas remains unaffected.
    • On increasing pressure, solubility of gas increases & for solid and liquid, it remains unaffected.

 

  1. Classification on the basis of size of solute particles

You must have made a solution of sand in water, sugar in water and milk. They don’t look the same. Let us predict the nature of these solutions-

Difference between a true solution, colloid and a suspension

True Solution
Colloid
Suspension
1) A true solution is a homogenous mixture of solute and solvent

 

1) A colloid appears to be homogeneous but actually it is a heterogeneous mixture of solute and solvent
(1) A suspension is a heterogeneous mixture of a solid dispersed in a liquid or a gas.
(2) In a true solution the size of particle is about 10-10m
(2) In a colloid the size of particles is in between 10-7 and 10-9 m
(2) In a suspension the size of particles is greater than 10-7 m
(3) In a true solution the solute particles cannot be seen even with a powerful microscope
3) In a colloid the dispersed particles can be seen with a powerful microscope
(3) In a suspension the dispersed particles can be seen with the naked eye
(4) The entire solution passes through filter paper
(4) The particles can pass through ordinary filter paper
(4) The particles cannot pass through filter paper
(5) The solute particles do not show tyndall effect
(5) The particles show tyndall effect
(5) The particles may or may not show tyndall effect
6) The particles do not settle due to gravity
(6) The particles do not settle due to gravity
(6) The particles may settle due to gravity

 

 

Separation of mixtures

  1. To obtain colored component (dye) from Ink

Materials Required

  • Watch glass
  • Ink (blue/ black)
  • Beaker
  • Stand
  • Burner.

 

Procedure

    1. Take a beaker and fill it half with water.
    2. Take few ml of ink (Blue/ black) in the watch glass and place it on the mouth of the beaker.
separation of mixtures
  1. Start heating the beaker and observe.
  2. Heating is continued as long as the evaporation is taking place
  3. Heating is stopped when no further change can be noticed on the watch glass

 

Observation

  1. Evaporation taking place from the watch glass can be seen
  2. Residue is left on the watch glass

 

Conclusion drawn

  1. It can be concluded that,” Ink is not a pure substance but it is a mixture of dye in water which can easily be separated by evaporation method”.
  2. Ink is not a single substance
  3. Evaporation taking place from the watch glass containing ink.

 

Applications of evaporation process are as follows-

  1. This method can be used to separate the volatile component (solvent) from its non-volatile solute.
  2. To obtain common salt from sea water. Sea water is trapped in small shallow pits (called lagoons) and is allowed to stand there for a few days. During this time the heat of the Sun evaporates water in these pits leaving behind the solid salt. This salt is further purified by crystallization method which you will study in the later part of this chapter.
  1. To separate cream from milk by using centrifugation method.
separate cream from milk

Materials Required

  1. Full cream milk
  2. Centrifuging machine/milk churner
  3. Jug test-tubes.

Procedure

  1. Take un boiled cold milk in two test-tubes and place these test-tubes in a centrifuging machine .
  2. Centrifuge it at high speed by using a hand centrifuging machine for two minute and observe.

 

Note
If you don’t have centrifuging machine in your school then you can do this activity by using a milk churner used in the kitchen.

Observation
Cream floating on the milk can be seen.

Conclusion drawn:
When milk is rotated at high speed, then the suspended lighter particles (fats and protein molecules) bind with each other forming ‘cream’ and ‘skimmed milk’. The cream being lighter, floats over the skimmed milk which can be removed easily.

Applications of centrifugation method are as follows-

  1. This technique is used in washing machines to squeeze out water from wet clothes and make them dry.
  2. This technique is used in diagnostic laboratories for testing cholesterol lipids in blood, ESR (Erythrocyte Sedimentation Rate) and various other types of tests.
  3. It is used in dairies for separating cream from milk and butter from curd.
  1. To separate kerosene oil from water by using a separating funnel.
separate kerosene oil from water

Materials Required

  1. Separating funnel
  2. Iron stand
  3. kerosene oil
  4. Beaker
  5. Water.

Procedure

  1. A mixture of kerosene oil and water is taken in a separating funnel. The separating funnel is clamped on an iron stand.
  2. The mixture is allowed to stand so that it forms two distinct layers.
  3. A clean beaker is placed below and the stop cock is opened slowly so that water falls into the beaker.
  4. Close the stop- cock of the separating funnel as the oil reaches the stop cock.

Observation

Kerosene oil being lighter forms the upper layer.

Conclusion drawn:

When a liquid mixture containing two immiscible liquids is taken in a separating funnel, then the liquid layers stand one above the other. The liquid layer with greater density forms the lower layer whereas the lighter liquid (having lower density) forms the upper layer.

Applications of this method are as follows-

  1. They separate mixture of oil and water.
  2. In the extraction of iron from its ore, the lighter slag is removed from the top by this method to leave the molten iron at the bottom in the furnace.

 

4. To separate a mixture of common salt and ammonium chloride
Materials Required

  1. China dish
  2. Tripod stand
  3. Mixture of common salt and ammonium chloride
  4. Glass funnel
  5. Cotton
  6. Burner.
separate mixture of common salt

Procedure

  1. Take the mixture of sand and ammonium chloride in a china dish.
  2. Cover the china dish with an inverted glass funnel and place it on a tripod stand.
  3. Put a loose cotton plug in the opening of the funnel so as to prevent the escape of ammonium chloride vapours.
  4. Heat the china dish on a low flame and observe.

 

Observation

  1. White fumes (vapours) of ammonium chloride can be seen coming out of the mixture.
  2. These white fumes start depositing as white solid, on coming in contact with the cold, inner walls of the funnel.
  3. Sand salt is left behind in the china dish.

 

Conclusion drawn:
Ammonium chloride, being a volatile substance, changes into white vapours easily which deposit on the cold inner wall of the funnel. This ammonium chloride obtained and is called as Sublimate. Some other examples of solids which sublime are: Iodine, camphor, naphthalene and anthracene.

 

5. To separate the dyes (colored components) present in black ink.

Materials Required

  1. Strip of filter paper
  2. Water soluble ink ( sketch pen or fountain pen)
  3. Large size glass jar with lid
  4. Cotton
  5. Thread.
separate the dyes

Procedure

  1. Take a thin strip of filter paper (25cm x 5cm approx).
  2. Draw a line on it using a pencil, approximately 3cm above the lower edge.
  3. Put a small drop of water soluble black ink from a sketch pen or fountain pen) at the centre of the line. Let the ink dry.
  4. Attach the paper strip on the thread with the help of cello tape.
  5. Lower the filter paper strip into a large size gas jar in such a way that the drop of ink on the paper is just above the water level.
  6. Adjust the thread and fix it on the sides of gas jar with the help of cello tape.
  7. Cover the gas jar with a lid and leave it undisturbed.
  8. Watch carefully as the water rises up on the filter paper.
  9. Remove the filter paper strip, dry it and observe.

 

Observation

Three colored spots can be seen on the filter paper strip.

Conclusion

The given sample of black ink has three different dyes mixed in it.

 

6. To separate a mixture of two miscible liquids (acetone and water).

Materials Required

  1. Distillation flask
  2. Thermometer
  3. Condenser
  4. Beaker
  5. Iron stand
  6. Mixture of acetone and water.

 

Procedure

  1. Take the mixture in a distillation flask. Fit the flask with a thermometer.
  2. Arrange the apparatus as shown in the figure.
  3. Heat the mixture slowly, keeping a close watch at the thermometer and observe what happens.

 

Observation

  1. The vapours of acetone can be seen rising up in the distillation flask with the increase in temperature.
  2. When the temperature rises above 60o, the acetone gets vapourized and forms vapours in the flask.
  3. These vapours get condensed in the condenser and can be collected (as pure liquid distillate) from the condenser outlet.

 

Result

Acetone can be collected in the beaker from the condenser outlet while water is left behind in the distillation flask.

 

7. To obtain crystals of pure copper sulphate salt from an impure sample by crystallization method.

obtain crystals

Materials Required

  1. Impure sample of copper sulphate
  2. Beaker
  3. China dish
  4. Glass rod.

Procedure

  1. Take about 5 grams of impure sample of copper sulphate in a china dish.
  2. Dissolve it in minimum amount of water.
  3. Filter the copper sulphate solution to remove the insoluble impurities.
  4. Heat the copper sulphate solution gently on a water bath until it becomes saturated and reaches its crystallization point.
  5. Crystallization point can be checked by taking some solution on a glass rod and waving it in the air. When a solid film (small crystals) is formed on the glass rod, then further heating is stopped. This indicates that the solution has been concentrated to crystallization point.
  6. Place the china dish on the table after covering it with a watch glass. Leave it undisturbed at room temperature to cool slowly for a day and observe thereafter.

 

Observation

Crystals of copper sulphate can be seen in the china dish along with the mother liquor (the residual liquid which is left after crystallization).

Conclusions drawn
Hot and concentrated solution of any pure substance forms crystal on cooling gradually.

Result: Pure crystals of copper sulphate are separated from the mother liquor. These crystals are dried further between the folds of a filter paper or on a porous plate.

 

8. Purification of surface water

The purification of surface water can be done through following steps-

Sedimentation → loading → filtration → chlorination.

  1. Sedimentation: The river water is pumped into a series of sedimentation tanks where it is allowed to stay for a day. Heavy particles of clay and other impurities settle down at the bottom due to the effect of gravity. The supernatant water is then sent to another settling tank.
  2. Loading: In next chamber, water is treated with chemicals, i.e. alum and lime to get further settling of impurities.
  3. Filtration: The clear water from the second tank is pumped into filtration tank where sand and gravel filter completely remove the suspended impurities.
  4. Chlorination: The clear water is chlorinated with a calculated amount of chlorine in the chlorination tank. This process kills harmful bacteria and germs and provides safe drinking water.

 

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Physical and chemical change

We observe different kind of changes around us like if you forget to keep the milk inside the fridge in summers it gets rancid, likewise when you keep ice out of the refrigerator, you observe the water around it and finally the ice gets converted into water. These all are changes that are taking place around us. But some changes can be reversed like water can be converted back to ice but rancid food item can not be made fresh again. Let us learn in detail about these changes.

 

  1. Physical change
  2. Chemical change

 

Physical change
Chemical change
no new substance is formed
Mass does not change
Energy is neither absorbed nor released
Reversible in nature
For example:
Glowing of bulb
Sublimation of camphor
Magnetizing iron
a new substance is formed
Mass changes
Energy is absorbed or released
Irreversible in nature
For example:
rusting of iron
Burning of magnesium
Reacting metal with acids

 

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Is Matter around us Class 9 Questions and Answers

Q1. What is pure substance?

Ans: A pure substance is a substance that contains the same kind of particles and has definite properties.

 

Q2. What is the difference between homogeneous and heterogeneous mixtures?

Ans :

Homogenous mixtures

Heterogeneous mixtures

1.it consists of a single phase
1. It consists of two or more phases
2.it has a uniform composition
2. It doesn’t have a uniform composition
3.There are no visible boundaries between components
3. There are visible boundaries
4.example : sodium chloride in water
4. Example : sand in water

 

Q3. To make a saturated solution, 36g of sodium chloride is dissolved in 100g of water at 293K.Find the concentration of solution?

Ans: Mass of sodium chloride = 36g

Mass of water =100g

Total mass of solution =100+36=136g

Mass percentage of solution=mass of solute /mass of solution x 100

That is : 36/136 x 100=26.47%

 

Q4. How will you separate a mixture containing kerosene and petrol which are miscible with each other?
Ans : We will separate a mixture containing kerosene and petrol by distillation.

 

Q5. Name the technique used to separate :

  • Butter from curd
  • Salt from sea water
  • Camphor from salt

Ans :

  1. Butter from curd – Centrifugation
  2. Salt from seawater – Evaporation
  3. Camphor from salt – Sublimation

 

Q6. Classify the following as Physical and chemical change.

  • Cutting of trees
  • Melting of butter in pan
  • Rusting of almirah
  • Boiling of water to form steam
  • Passing an electric current through water
  • Dissolving salt in water
  • Making a fruit salad
  • Burning of paper or wood

Ans.

  1. Cutting of trees – physical change
  2. Melting of butter in pan- Physical change
  3. Rusting of almirah- chemical change
  4. Boiling of water to form steam- Physical change
  5. Passing an electric current through water – chemical change
  6. Dissolving salt in water- Physical change
  7. Making a fruit salad – physical change
  8. Burning of paper or wood – chemical change

 

Q7. Try to segregate the things around as pure substance or mixtures :

  • Water
  • Milk
  • LPG
  • Bread
  • Gold
  • Kerosene oil
  • Air
  • Paper
  • Common salt
  • Ink
  • Curd
  • Wood
  • Ice
  • Sugar
  • Soda water
  • Ice cream
  • Butter
  • Vanaspati ghee
  • Lemon juice
  • Brass

Ans.

  1. Water- Pure substance
  2. Milk-Mixture
  3. LPG-Mixture
  4. Bread-Mixture
  5. Gold-Pure substance
  6. Kerosene oil-Mixture
  7. Air-Mixture
  8. Paper-Mixture
  9. Common salt-Pure substance
  10. Ink-Mixture
  11. Curd-Mixture
  12. Wood-Mixture
  13. Ice-Pure substance
  14. Sugar- Pure substance
  15. Soda water-Mixture
  16. Ice cream-Mixture
  17. Butter-Mixture
  18. Vanaspati ghee-Mixture
  19. Lemon juice –Mixture
  20. Brass- Mixture

 

Q8. How are colloids, True solution and suspension different from each other?
Ans :

True Solution
Colloid
Suspension
1) A true solution is a homogeneous mixture of solute and solvent

 

1) A colloid appears to be homogeneous but actually it is a heterogeneous mixture of solute and solvent
(1) A suspension is a heterogeneous mixture of a solid dispersed in a liquid or a gas.
(2) In a true solution the size of particle is about 10-10m
(2) In a colloid the size of particles is in between 10-7 and 10-9 m
(2) In a suspension the size of particles is greater than 10-7 m
(3) In a true solution the solute particles cannot be seen even with a powerful microscope
3) In a colloid the dispersed particles can be seen with a powerful microscope
(3) In a suspension the dispersed particles can be seen with the naked eyes
(4) The entire solution passes through filter paper
(4) The particles can pass through ordinary filter paper
(4) The particles cannot pass through filter paper
(5) The solute particles do not show tyndall effect
(5) The particles show tyndall effect
(5) The particles may or may not show tyndall effect
6) The particles do not settle due to gravity
(6) The particles do not settle due to gravity
(6) The particles may settle due to gravity

 

Q9. Which separation techniques will you apply for the separation of the following?

  1. Sodium chloride from solution in water
  2. Ammonium chloride from a mixture of sodium chloride and ammonium chloride
  3. Small pieces of metal in engine oil of a car
  4. Different pigments from extract of flower petals
  5. Butter from curd
  6. Oil from water
  7. Tea leaves from tea
  8. Iron pins from sand
  9. Wheat grains from husk
  10. Fine mud particles suspended in water

Ans.

  1. Sodium chloride from solution in water- Evaporation
  2. Ammonium chloride from a mixture of sodium chloride and ammonium chloride – Sublimation
  3. Small pieces of metal in engine oil of a car- filtration
  4. Different pigments from extract of flower petals –Chromatography
  5. Butter from curd – Centrifugation
  6. Oil from water – Separating funnel
  7. Tea leaves from tea – Filtration
  8. Iron pins from sand –Magnetic separation
  9. Wheat grains from husk- Gravity separation
  10. Fine mud particles suspended in water – Centrifugation

 

Q10. Write the steps you would use for making tea.

Ans :
Step 1: Boil some solvent (water) in a pan.
Step 2: Put some solute (tea leaves) in water.
Step 3: Pour the boiling water in a tea pot and let it soak for few minutes to form a solution.
Step 4: Take some sugar in a cup.
Step 5: Filter the above solution using strainer and take the solution in a cup. Pour two spoons of milk and stir it. This gives us tea ready to drink.

 

Q11. Pragya tested the solubility of three different substances at different temperatures and collected the data as given below (results are given in the following table, as grams of substance dissolved in 100 grams of water to form a saturated solution).

 

 

Substance dissolved

Temperature in k

283

293

313

333

353

Solubility

Pottasium nitrate

21

32

62

106

167

Sodium chloride

36

36

36

37

37

Pottasium chloride

35

35

40

46

54

Ammonium chloride

24

37

41

55

66

 

(a) What mass of potassium nitrate would be needed to produce a saturated solution of potassium nitrate in 50 grams of water at 313 K?
(b) Pragya makes a saturated solution of potassium chloride in water at 353 K and leaves the solution to cool at room temperature. What would she observe as the solution cools? Explain.
(c) Find the solubility of each salt at 293 K. Which salt has the highest solubility at this temperature?
(d) What is the effect of change of temperature on the solubility of a salt?

Ans.
(a) At 313K, 62g of potassium nitrate dissolved in 100g of water. So, to produce a saturated solution of potassium nitrate in 50g of water,
we need

62/100 * 50 = 31 grams of potassium nitrate.

(b)Some soluble potassium chloride will separate out in the form of crystasl at room temperature because the solubility of potassium chloride will decrease.
(c)
(i) Solubility of Potassium nitrate at 293K is 32g.
(ii) Solubility of sodium chloride at 293K is 36g.
(iii) Solubility of Potassium chloride at 293K is 35g.
(iv) Solubility of Ammonium chloride at 293K is 37g.
The solubility of Ammonium chloride is highest at this temperature.
(d)The solubility of salt increases with the increase in temperature.

 

Q12. Explain the following giving examples.

  • saturated solution
  • pure substance
  • colloid
  • suspension

Ans.

  • Saturated solution: the solution that cannot dissolve much solute at a given temperature. Example: 50g of NaCl is added to 100g of water.
  • Pure substance – substance that contains the same kind of particles. Example: silicon.
  • Colloid – the solution whose solute particles are neither too small nor too large. For example: milk.
  • Suspension: the solution whose solute size is very big .Example: sand in water.

 

Q13. Classify each of the following as a homogeneous or heterogeneous mixture:

  • Soda water
  • Wood
  • Air
  • soil
  • Vinegar
  • filtered tea

Ans.

  1. Soda water – homogeneous mixture
  2. Wood – heterogeneous mixture
  3. Air- homogeneous mixture
  4. soil – heterogeneous mixture
  5. Vinegar- homogeneous mixture
  6. filtered tea – homogeneous mixture

 

Q14. How would you confirm that a colorless liquid given to you is pure water?

Ans: We will confirm that a colorless liquid given to us is pure water by checking it’s melting and boiling point.

 

Q15. Which of the following falls in the category of a ‘pure substance’?

  • Ice
  • Milk
  • Iron
  • Hydrochloric acid
  • Calcium oxide
  • Mercury
  • Brick
  • Wood
  • Air

Ans.

  1. Ice- Yes
  2. Milk-No
  3. Iron-Yes
  4. Hydrochloric acid –Yes
  5. Calcium oxide-Yes
  6. Mercury-Yes
  7. Brick-No
  8. Wood-No
  9. Air-No

 

Q16. Identify the solutions among the following mixtures:

  • Soil
  • Sea water
  • Air
  • Coal
  • Soda water

Ans.

  1. Soil – not a solution
  2. Sea water- is a solution
  3. Air- is a solution
  4. Coal- not a solution
  5. Soda water – is a solution

 

Q17. Which of the following show Tyndall effect :

  • Salt solution
  • Milk
  • Copper sulphate solution
  • Starch solution

Ans.

  1. Salt solution –No
  2. Milk-Yes
  3. Copper sulphate solution-No

Starch solution – yes

 

Q18. Classify the following into Elements, Compounds and Mixtures.

  • Sodium
  • Soil
  • Sugar solution
  • Silver
  • Calcium carbonate
  • Tin
  • Silicon
  • Coal
  • Air
  • Soap
  • Methane
  • Carbon dioxide
  • Blood

Ans.

  1. Sodium – element
  2. Soil – Mixture
  3. Sugar solution- Mixture
  4. Silver- element
  5. Calcium carbonate- compound
  6. Tin- element
  7. Silicon- element
  8. Coal- Mixture
  9. Air- mixture
  10. Soap- compound
  11. Methane- Compound
  12. Carbon dioxide- compound
  13. Blood – mixture

 

Q19. Which of the following are chemical changes?

  • Growth of plant
  • Rusting of iron
  • Mixing of iron filings and sand
  • Cooking of food
  • Digestion of food
  • Freezing of water
  • Burning of candle

Ans.

  1. Growth of plant –yes
  2. Rusting of iron- yes
  3. Mixing of iron filings and sand- No
  4. Cooking of food- yes
  5. Digestion of food – yes
  6. Freezing of water-No
  7. Burning of candle- yes

 

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